Dec 14, 2015 · int csc (x)dx = lnabs (csc (x) - cot (x)) + C As is often with integrals, there are a couple of different ways to solve this.

Explanation: you can ignore the 7 because multiplying #csc (4x)# by a constant doesn't change whether a y-value exists at that point or not.

Questions and Videos on Graphing Tangent, Cotangent, Secant, and Cosecant, within Trigonometry

Mar 30, 2018 · Match each equation number with a equivalent letter, and then prove each one. (1.): (csc (x) - sin (x)) (2.): (sin (x)/ (sin (x)+ cos (x)) (3.): (2 sin 4 (x)) (cos 4 ...

(A) But as |cscx|>=1, hence cscx+1/3!=0 and hence we can divide A by (cscx+1/3) and we get 2sinx+sqrt3=0 or sinx=-sqrt3/2=sin ( (4pi)/3) or sinx=sin ( (5pi)/3) Hence, while in general …

Explanation: #a. sec x = 1/sin x = -2/3 --> sin x = -3/2# (impossible) b. # tan x = 1. 4# (possible) c. #csc x = 1/ sin x = 5# --> #sin x = 1/5# (possible)

3 Answers 1s2s2p Jan 9, 2018 #cscx-=1/sinx# #secx-=1/cosx# So, now we have: # (cosx+sinx) (1/cosx+1/sinx)# We can now expand this to get: # (cosx*1/cosx)+ (sinx*1 ...

How do you solve for all real values of x with the following equation 2 sin x + csc x = 3 ??

While the cosecant has a tabled, standard derivative we can work with the sine too, if you don't remember / don't have a standard derivative table handy.

Mar 31, 2018 · Assuming that you mean: int (cos (x)-sin^2 (x))/ (sin (x)cos (x)) dx Separate into two integrals: int (cos (x)-sin^2 (x))/ (sin (x)cos (x)) dx = int cos (x)/ (sin (x)cos (x)) dx -int sin^2 …